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Average Speed -2

1
Unequal Speeds and Equal Time Intervals

A car travels with speeds v₁ and v₂ for equal time intervals t and t respectively. The average speed of the car is:


A v₁ + v₂
B (v₁ + v₂) / 2
C 2v₁v₂ / (v₁ + v₂)
D v₁v₂ / (v₁ + v₂)
Show Answer & Solution

✓ Correct Answer: B — (v₁ + v₂) / 2

🧠 Concept

How to analyse the problem: The speeds are unequal: v1 and v2, while the time intervals are equal: t, t.

How to crack it: Start from average speed = total distance ÷ total time. Since the time intervals are equal, find each distance using d = vt.

vavg = Total distance Total time

d = vt

Therefore, for equal time intervals:

d1 = v1t     d2 = v2t

vavg = v1t + v2t t + t

vavg = t(v1 + v2) 2t

vavg = v1 + v2 2

Conclusion: When the time intervals are equal, the average speed is the arithmetic mean of the two speeds.

💡 Solution

Given:

First speed = v1
Second speed = v2
Both time intervals = t

Step 1: Find the distances

d1 = v1t     d2 = v2t

Step 2: Find total distance

Total distance = v1t + v2t

Step 3: Find total time

Total time = t + t = 2t

Step 4: Calculate average speed

vavg = v1t + v2t 2t

Cancel the common factor t:

vavg = v1 + v2 2

Answer: vavg = (v1 + v2) / 2




2
Equal Speeds and Equal Time Intervals

A car travels with the same speed v for two equal time intervals t and t respectively. The average speed of the car is:


A v / 2
B v
C 2v
D
Show Answer & Solution

✓ Correct Answer: B — v

🧠 Concept

How to analyse the problem: The car moves with the same speed v during both time intervals. Since the speed does not change, the average speed must also be v.

How to crack it: Start with the basic definition of average speed:

vavg = Total distance Total time

Basic formula:

vavg = d1 + d2 t1 + t2

Since the speed is v:

d1 = vt     and     d2 = vt

Derived formula:

vavg = vt + vt t + t = v

Conclusion: When the speed remains the same, the average speed is equal to that constant speed, regardless of the equal time intervals.

💡 Solution

Given:

v1 = v2 = v
t1 = t2 = t

Distance covered in the first interval:

d1 = vt

Distance covered in the second interval:

d2 = vt

Therefore,

vavg = vt + vt t + t

Taking v and t common:

vavg = 2vt 2t = v
Answer: (2) v




3
Starts from Rest + Uniform Acceleration

A car is initially at rest and accelerates uniformly at 5 m/s². What is its average speed during the first 10 seconds?


A 10 m/s
B 20 m/s
C 25 m/s
D 50 m/s
Show Answer & Solution

✓ Correct Answer: B — 20 m/s

🧠 Concept

How to analyse the problem: The car starts from rest, so its initial speed is zero. Since the car accelerates uniformly, its velocity increases at a constant rate.

How to crack it: For uniformly accelerated motion, the average speed is the arithmetic mean of the initial and final speeds. First find the final speed using the equation of motion.

Basic formulas:

v = u + at
vavg = u + v 2

Since the car starts from rest:

u = 0

Therefore, the formulas become:

v = at
vavg = at 2

Conclusion: For a body starting from rest and moving with uniform acceleration, the average speed during time t is at/2.

💡 Solution

Given:

u = 0
a = 5 m/s²
t = 10 s

First, find the final speed:

v = u + at
v = 0 + (5)(10)
v = 50 m/s

Now calculate the average speed:

vavg = u + v 2
vavg = 0 + 50 2
vavg = 25 m/s
Answer: (3) 25 m/s




4
Starts from Rest + Non-Uniform Acceleration

A car starts from rest and moves with non-uniform acceleration. Which expression should be used to determine its average speed over a time interval t?


A (u + v) / 2
B at / 2
C Total distance / Total time
D v - u / t
Show Answer & Solution

✓ Correct Answer: C — Total distance / Total time

🧠 Concept

How to analyse the problem: The car starts from rest, so its initial speed is zero. However, the acceleration is non-uniform, meaning the acceleration is not constant throughout the motion.

How to crack it: When acceleration is non-uniform, we cannot directly use the uniform-acceleration formula vavg = (u + v)/2. Instead, always return to the definition of average speed.

Basic formula:

vavg = Total distance Total time

Since the car starts from rest:

u = 0

But the condition of starting from rest alone is not enough to determine the average speed. The distance travelled must be known or determined from the actual motion.

Derived form:

vavg = s t

Conclusion: For non-uniform acceleration, use the fundamental definition of average speed: total distance divided by total time. The shortcut (u + v)/2 cannot be used unless the acceleration is uniform.

💡 Solution

The car starts from rest, so:

u = 0

But the acceleration is non-uniform. Therefore, the uniform-acceleration relation vavg = (u + v)/2 is not generally valid.

We must use the definition of average speed:

vavg = Total distance Total time

Therefore, if the total distance travelled is s during time t:

vavg = s t
Answer: (3) Total distance / Total time




5
Starts from Rest + Non-Uniform Acceleration

A car starts from rest. During the first 5 s, it travels 20 m, and during the next 5 s, it travels 40 m. What is its average speed during the entire 10 s?


A 4 m/s
B 5 m/s
C 6 m/s
D 8 m/s
Show Answer & Solution

✓ Correct Answer: B — 5 m/s

🧠 Concept

How to analyse the problem: The car starts from rest, but its acceleration is non-uniform. Therefore, we should not use the uniform-acceleration shortcut vavg = (u + v)/2.

How to crack it: When the motion is non-uniformly accelerated, divide the motion into the given intervals, find the total distance and total time, and then use the definition of average speed.

Basic formula:

vavg = Total distance Total time

For two intervals:

vavg = d1 + d2 t1 + t2

Conclusion: For non-uniform acceleration, average speed is determined from total distance and total time. The initial condition of rest does not make the uniform-acceleration formula applicable.

💡 Solution

Given:

d1 = 20 m
d2 = 40 m
t1 = 5 s
t2 = 5 s

Total distance travelled:

d = d1 + d2
d = 20 + 40 = 60 m

Total time:

t = t1 + t2
t = 5 + 5 = 10 s

Therefore, the average speed is:

vavg = 60 10
vavg = 6 m/s
Answer: (3) 6 m/s




6
Starts from Rest + Non-Uniform Acceleration as a Function of Time

A car starts from rest and its acceleration varies with time according to a(t) = 2t m/s², where t is in seconds. What is its average speed during the first 4 seconds?


A 4 m/s
B 8 m/s
C 16/3 m/s
D 32/3 m/s
Show Answer & Solution

✓ Correct Answer: C — 16/3 m/s

🧠 Concept

How to analyse the problem: The car starts from rest, but its acceleration is not constant. Instead, acceleration is given as a function of time.

How to crack it: For non-uniform acceleration, do not use vavg = (u + v)/2. First obtain velocity from acceleration and then obtain displacement from velocity.

Basic formulas:

a = dv dt
v = ds dt

Therefore, when a(t) is known:

v(t) = ∫ a(t) dt
s(t) = ∫ v(t) dt

Finally, average speed is obtained from:

vavg = Total distance Total time

Conclusion: When acceleration is a function of time, use integration to find velocity and displacement. Then use total distance divided by total time to obtain average speed.

💡 Solution

Given:

u = 0
a(t) = 2t
T = 4 s

Since a = dv/dt:

dv = 2t dt

Integrating from 0 to t:

v(t) = ∫0t 2t dt
v(t) = t²

Now find the distance travelled:

s = ∫04 v(t) dt
s = ∫04 t² dt
s = 3 = 64/3 m

Therefore:

vavg = 64/3 4
vavg = 16/3 m/s
Answer: (3) 16/3 m/s




7
Initial Velocity + Uniform Acceleration

A car is moving initially at 10 m/s and accelerates uniformly at 4 m/s² for 5 s. What is its average speed during this interval?


A 15 m/s
B 20 m/s
C 25 m/s
D 30 m/s
Show Answer & Solution

✓ Correct Answer: B — 20 m/s

🧠 Concept

How to analyse the problem: The car already has an initial speed u, and then it accelerates uniformly. Therefore, both the initial and final speeds are different.

How to crack it: First find the final speed using the first equation of motion. Since acceleration is uniform, the average speed is the arithmetic mean of the initial and final speeds.

Basic formulas:

v = u + at
vavg = u + v 2

Substituting v = u + at into the average-speed formula:

vavg = u + (u + at) 2
vavg = u + at 2

Conclusion: For initial velocity u and uniform acceleration a acting for time t, the average speed is u + at/2.

💡 Solution

Given:

u = 10 m/s
a = 4 m/s²
t = 5 s

First, find the final speed:

v = u + at
v = 10 + (4)(5)
v = 30 m/s

Since the acceleration is uniform:

vavg = u + v 2
vavg = 10 + 30 2
vavg = 20 m/s
Answer: (2) 20 m/s




8
Uniform Retardation

A car is moving with an initial speed of 30 m/s and undergoes uniform retardation of 5 m/s² for 4 s. What is its average speed during this interval?


A 15 m/s
B 20 m/s
C 25 m/s
D 30 m/s
Show Answer & Solution

✓ Correct Answer: B — 20 m/s

🧠 Concept

How to analyse the problem: The car is initially moving with speed u and its speed decreases uniformly due to retardation. Since the retardation is uniform, the acceleration is constant and negative.

How to crack it: Treat retardation as negative acceleration. First find the final speed using the equation of motion. Then use the average-speed formula for uniformly accelerated motion.

Basic formulas:

v = u + at

For retardation of magnitude r:

a = -r
v = u - rt

For uniform retardation, the average speed is:

vavg = u + v 2

Substituting v = u - rt:

vavg = u + (u - rt) 2
vavg = u - rt 2

Conclusion: During uniform retardation, the average speed is the arithmetic mean of the initial and final speeds, provided the object continues moving in the same direction throughout the interval.

💡 Solution

Given:

u = 30 m/s
r = 5 m/s²
t = 4 s

Retardation is opposite to the direction of motion, so:

a = -5 m/s²

Find the final speed:

v = u + at
v = 30 + (-5)(4)
v = 10 m/s

Now calculate the average speed:

vavg = u + v 2
vavg = 30 + 10 2
vavg = 20 m/s
Answer: (2) 20 m/s




9
Given Distance and Time + Uniform Acceleration

A car starts from rest and moves with uniform acceleration. It covers a distance of 100 m in 5 s. What is its average speed during this interval?


A 10 m/s
B 15 m/s
C 20 m/s
D 25 m/s
Show Answer & Solution

✓ Correct Answer: C — 20 m/s

🧠 Concept

How to analyse the problem: The car starts from rest and moves with uniform acceleration. The distance and time are directly given, so average speed can be found immediately from its definition.

How to crack it: Do not unnecessarily find acceleration or final velocity. When total distance and total time are already given, directly use total distance divided by total time.

Basic formula:

vavg = Total distance Total time

For distance s covered in time t:

vavg = s t

Since the car starts from rest and acceleration is uniform:

s = 1 2 at²

Therefore:

vavg = at 2

Conclusion: When distance and time are given, average speed is simply distance divided by time. The uniform-acceleration condition provides additional information but is not needed for this direct calculation.

💡 Solution

Given:

s = 100 m
t = 5 s

Average speed is:

vavg = s t
vavg = 100 5
vavg = 20 m/s
Answer: (3) 20 m/s




10
Given Initial and Final Speeds + Uniform Acceleration

A car moves with uniform acceleration. Its speed increases from 10 m/s to 30 m/s. What is its average speed during this interval?


A 10 m/s
B 15 m/s
C 20 m/s
D 30 m/s
Show Answer & Solution

✓ Correct Answer: C — 20 m/s

🧠 Concept

How to analyse the problem: The initial speed and final speed are given directly. Since the acceleration is uniform, the velocity changes uniformly with time.

How to crack it: When initial and final speeds are known and acceleration is uniform, there is no need to find acceleration, distance, or time. Directly take the arithmetic mean of the initial and final speeds.

Basic formula:

vavg = u + v 2

This result follows from uniform acceleration because the velocity changes linearly with time.

Using the equation:

v = u + at

The average speed can also be written as:

vavg = u + at 2

Conclusion: For uniform acceleration, when the initial and final speeds are given, average speed is the arithmetic mean of those two speeds.

💡 Solution

Given:

u = 10 m/s
v = 30 m/s

Since the acceleration is uniform, use:

vavg = u + v 2
vavg = 10 + 30 2
vavg = 20 m/s
Answer: (3) 20 m/s