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Average Speed -3

1
Acceleration Changes in Different Time Intervals

A car starts from rest. It accelerates uniformly at 2 m/s² for 5 s and then accelerates uniformly at 4 m/s² for the next 5 s. What is its average speed during the entire 10 s?


A 10 m/s
B 12.5 m/s
C 15 m/s
D 20 m/s
Show Answer & Solution

✓ Correct Answer: C — 15 m/s

🧠 Concept

How to analyse the problem: The acceleration changes after the first time interval. Therefore, the motion must be treated as two separate uniformly accelerated stages.

How to crack it: Solve each time interval separately. The final velocity of the first interval becomes the initial velocity of the second interval. Find the distance covered in each interval, add them, and divide by the total time.

Basic formula:

s = ut + 1 2 at²

For multiple intervals:

stotal = s1 + s2 + ...

Total time:

ttotal = t1 + t2 + ...

Therefore:

vavg = stotal ttotal

Conclusion: When acceleration changes from one time interval to another, calculate each stage separately and use total distance divided by total time. Do not simply average the accelerations.

💡 Solution

First interval:

u1 = 0
a1 = 2 m/s²
t1 = 5 s

Distance covered in the first interval:

s1 = u1t1 + 1 2 a1t1²
s1 = 0 + 1 2 (2)(25)
s1 = 25 m

Speed at the end of the first interval:

v1 = u1 + a1t1
v1 = 0 + (2)(5) = 10 m/s

Second interval:

u2 = v1 = 10 m/s
a2 = 4 m/s²
t2 = 5 s

Distance covered in the second interval:

s2 = u2t2 + 1 2 a2t2²
s2 = (10)(5) + 1 2 (4)(25)
s2 = 100 m

Total distance:

stotal = 25 + 100 = 125 m

Total time:

ttotal = 5 + 5 = 10 s

Therefore:

vavg = 125 10 = 12.5 m/s
Answer: (2) 12.5 m/s




2
Acceleration over Different Distance Intervals

A car starts from rest. It accelerates uniformly at 2 m/s² while covering the first 25 m, and then accelerates uniformly at 4 m/s² while covering the next 100 m. What is its average speed over the entire 125 m distance?


A 10 m/s
B 12.5 m/s
C 15 m/s
D 20 m/s
Show Answer & Solution

✓ Correct Answer: C — 15 m/s

🧠 Concept

How to analyse the problem: The acceleration changes after a specified distance rather than after a specified time. Therefore, the motion must be divided into separate distance intervals.

How to crack it: For each distance interval, find the time taken using the appropriate equation of motion. The final velocity of one interval becomes the initial velocity of the next interval. Finally, add all the times and use total distance divided by total time.

Basic formulas:

v² = u² + 2as
s = ut + 1 2 at²

For each distance interval:

vi² = ui² + 2aisi

Total time is:

ttotal = t1 + t2 + ...

Therefore:

vavg = stotal ttotal

Conclusion: When acceleration changes after different distances, solve each distance interval separately. The average speed is always obtained from total distance divided by total time.

💡 Solution

First distance interval:

u1 = 0
a1 = 2 m/s²
s1 = 25 m

Find the velocity at the end of the first interval:

v1² = u1² + 2a1s1
v1² = 0 + 2(2)(25)
v1 = 10 m/s

Now find the time for the first interval:

v1 = u1 + a1t1
10 = 0 + 2t1
t1 = 5 s

Second distance interval:

u2 = v1 = 10 m/s
a2 = 4 m/s²
s2 = 100 m

Find the final velocity:

v2² = u2² + 2a2s2
v2² = 10² + 2(4)(100)
v2 = 30 m/s

Find the time for the second interval:

v2 = u2 + a2t2
30 = 10 + 4t2
t2 = 5 s

Total distance:

stotal = 25 + 100 = 125 m

Total time:

ttotal = 5 + 5 = 10 s

Therefore:

vavg = 125 10 = 12.5 m/s
Answer: (2) 12.5 m/s




3
Mixed Uniform Acceleration + Uniform Speed

A car starts from rest and accelerates uniformly at 4 m/s² for 5 s. It then continues with the speed reached at the end of the acceleration for another 5 s. What is its average speed for the entire 10 s?


A 10 m/s
B 15 m/s
C 20 m/s
D 25 m/s
Show Answer & Solution

✓ Correct Answer: B — 15 m/s

🧠 Concept

How to analyse the problem: The motion has two different stages. In the first stage, the car accelerates uniformly. In the second stage, it moves with uniform speed.

How to crack it: Treat each stage separately. Find the distance covered during the accelerated stage and then the distance covered during the uniform speed stage. Add the distances and divide by the total time.

Basic formulas:

s = ut + 1 2 at²
v = u + at

For the uniform-speed stage:

s = vt

Finally:

vavg = stotal ttotal

Conclusion: When a journey contains both uniformly accelerated motion and uniform-speed motion, solve each stage separately and use total distance divided by total time.

💡 Solution

Stage 1: Uniform acceleration

u = 0
a = 4 m/s²
t1 = 5 s

Distance covered during acceleration:

s1 = ut + 1 2 at²
s1 = 1 2 (4)(25)
s1 = 50 m

Speed reached at the end of Stage 1:

v = u + at
v = 0 + (4)(5)
v = 20 m/s

Stage 2: Uniform speed

The car continues at 20 m/s for another 5 s.

s2 = vt
s2 = (20)(5)
s2 = 100 m

Total distance:

stotal = 50 + 100 = 150 m

Total time:

ttotal = 5 + 5 = 10 s

Therefore:

vavg = 150 10 = 15 m/s
Answer: (2) 15 m/s




4
Full Circle — One Revolution

A car moves along a circular track of radius 7 m and completes one complete revolution in 11 s. What is its average speed? Take π = 22/7.


A 2 m/s
B 4 m/s
C 6 m/s
D 8 m/s
Show Answer & Solution

✓ Correct Answer: B — 4 m/s

🧠 Concept

How to analyse the problem: The car moves along a complete circular path. Therefore, the distance travelled is equal to the circumference of the circle.

How to crack it: First find the circumference of the circle. This gives the total distance travelled in one complete revolution. Then divide the total distance by the total time.

Basic formula:

vavg = stotal ttotal

For one complete revolution, the distance travelled is the circumference:

s = 2πr

Therefore, for one complete revolution:

vavg = 2πr t

Conclusion: For one complete revolution, use the circumference 2πr as the total distance and divide it by the total time.

💡 Solution

Step 1: Find the distance travelled

The car completes one complete revolution. Therefore, the distance travelled is the circumference of the circle.

s = 2πr
s = 2 × 22 7 × 7
s = 44 m

Step 2: Find the average speed

Total time taken is 11 s.

vavg = stotal ttotal
vavg = 44 11
vavg = 4 m/s
Answer: (2) 4 m/s




5
Semicircle — Half Revolution

A particle moves along a semicircular path of radius 14 m in 22 s. What is its average speed? Take π = 22/7.


A 1 m/s
B 2 m/s
C 3 m/s
D 4 m/s
Show Answer & Solution

✓ Correct Answer: B — 2 m/s

🧠 Concept

How to analyse the problem: The particle moves along a semicircular path. A semicircle is half of a complete circular path, so its path length is half of the circumference.

How to crack it: Find the length of the semicircular path first. Then use total distance divided by total time to calculate average speed.

Basic formula:

vavg = stotal ttotal

The circumference of a complete circle is:

C = 2πr

Since a semicircle is half of a complete circle:

s = 2πr 2 = πr

Therefore:

vavg = πr t

Conclusion: For motion along a semicircular path, the actual distance travelled is πr. Use this curved distance when calculating average speed.

💡 Solution

Step 1: Find the distance travelled

The particle travels along a semicircle. Therefore, the distance travelled is:

s = πr
s = 22 7 × 14
s = 44 m

Step 2: Find the average speed

Total time taken is 22 s.

vavg = stotal ttotal
vavg = 44 22
vavg = 2 m/s
Answer: (2) 2 m/s




6
Quarter Circle — Quarter Revolution

A particle moves along a quarter-circular path of radius 14 m in 11 s. What is its average speed? Take π = 22/7.


A 1 m/s
B 2 m/s
C 3 m/s
D 4 m/s
Show Answer & Solution

✓ Correct Answer: B — 2 m/s

🧠 Concept

How to analyse the problem: The particle moves through one-fourth of a complete circular path. Therefore, the distance travelled is one-fourth of the circumference of the circle.

How to crack it: First find the circumference of the complete circle. Then take one-fourth of it to obtain the actual distance travelled along the quarter-circular path. Finally, divide the distance by the total time.

Basic formula:

vavg = stotal ttotal

Circumference of a complete circle:

C = 2πr

A quarter circle is one-fourth of the complete circumference:

s = 2πr 4 = πr 2

Therefore:

vavg = πr 2t

Conclusion: For a quarter-circular path, the actual distance travelled is πr/2. Average speed is obtained using this curved distance and the total time.

💡 Solution

Step 1: Find the distance travelled

The particle travels through one-fourth of a complete circle. Therefore:

s = 2πr 4
s = 22 7 × 14 ÷ 2
s = 22 m

Step 2: Find the average speed

Total time taken is 11 s.

vavg = stotal ttotal
vavg = 22 11
vavg = 2 m/s
Answer: (2) 2 m/s




7
Multiple Revolutions

A particle moves along a circular track of radius 7 m and completes 5 complete revolutions in 55 s. What is its average speed? Take π = 22/7.


A 2 m/s
B 4 m/s
C 6 m/s
D 8 m/s
Show Answer & Solution

✓ Correct Answer: B — 4 m/s

🧠 Concept

How to analyse the problem: The particle completes more than one revolution around the circular track. Therefore, the total distance is the distance covered in one revolution multiplied by the number of revolutions.

How to crack it: First find the circumference of the circular track. Then multiply it by the total number of revolutions to obtain the total distance. Finally, divide the total distance by the total time.

Basic formula:

vavg = stotal ttotal

Distance covered in one complete revolution:

sone = 2πr

If the particle completes n revolutions, the total distance is:

stotal = n(2πr)

Therefore:

vavg = n(2πr) t

Conclusion: For multiple complete revolutions, multiply the circumference by the number of revolutions to obtain the total distance.

💡 Solution

Step 1: Find the distance covered in one revolution

sone = 2πr
sone = 2 × 22 7 × 7
sone = 44 m

Step 2: Find the total distance

The particle completes 5 revolutions.

stotal = 5 × 44
stotal = 220 m

Step 3: Find the average speed

Total time taken is 55 s.

vavg = stotal ttotal
vavg = 220 55
vavg = 4 m/s
Answer: (2) 4 m/s




8
Circle + Straight-Line Motion

A particle completes one complete revolution around a circular track of radius 7 m and then moves 12 m along a straight line. The total time taken is 10 s. What is its average speed? Take π = 22/7.


A 5.2 m/s
B 5.6 m/s
C 6.0 m/s
D 6.4 m/s
Show Answer & Solution

✓ Correct Answer: B — 5.6 m/s

🧠 Concept

How to analyse the problem: The motion consists of two different parts. First, the particle travels along a complete circular path. Then it travels along a straight path. Therefore, the total distance is the sum of the distances covered in both parts.

How to crack it: Calculate the circular distance using the circumference formula. Then add the straight-line distance. Finally, divide the total distance by the total time.

Basic formulas:

scircle = 2πr
stotal = scircle + sstraight

Average speed is:

vavg = stotal ttotal

Conclusion: When a journey contains a circular part and a straight-line part, calculate the actual distance of each part separately, add them, and divide by the total time.

💡 Solution

Step 1: Find the circular distance

The particle completes one complete revolution.

scircle = 2πr
scircle = 2 × 22 7 × 7
scircle = 44 m

Step 2: Find the total distance

The straight-line distance is 12 m.

stotal = 44 + 12
stotal = 56 m

Step 3: Find the average speed

Total time taken is 10 s.

vavg = stotal ttotal
vavg = 56 10
vavg = 5.6 m/s
Answer: (2) 5.6 m/s




9
Distance vs Displacement on a Circular Path

A particle moves along a circular track of radius 14 m and completes one complete revolution in 22 s. What are its average speed and magnitude of average velocity respectively? Take π = 22/7.


A 2 m/s, 0 m/s
B 4 m/s, 0 m/s
C 0 m/s, 2 m/s
D 4 m/s, 4 m/s
Show Answer & Solution

✓ Correct Answer: B — 4 m/s, 0 m/s

🧠 Concept

How to analyse the problem: The particle completes one complete revolution and returns to its starting point. Therefore, the distance travelled is the complete circumference, while the displacement is zero.

How to crack it: For average speed, use the total distance travelled. For average velocity, use the displacement. Do not use displacement to calculate average speed.

Basic formulas:

Average Speed = Total Distance Total Time
Magnitude of Average Velocity = Magnitude of Displacement Total Time

For one complete revolution:

Distance = 2πr

Since the particle returns to its starting point:

Displacement = 0

Conclusion: After one complete revolution, the particle has travelled a non-zero distance but its displacement is zero. Therefore, average speed is non-zero, while average velocity is zero.

💡 Solution

Step 1: Find the total distance

The particle completes one complete revolution. Therefore, the distance travelled is the circumference of the circle.

s = 2πr
s = 2 × 22 7 × 14
s = 88 m

Step 2: Find the average speed

Total time taken is 22 s.

Average Speed = 88 22
Average Speed = 4 m/s

Step 3: Find the displacement

After one complete revolution, the particle returns to its initial position. Hence, its displacement is zero.

Displacement = 0

Therefore, the magnitude of average velocity is:

Average Velocity = 0 22
Average Velocity = 0 m/s
Answer: (2) 4 m/s, 0 m/s




10
Triangle — Motion Along All Three Sides

A particle moves along the three sides of an equilateral triangle of side 20 m. It takes 5 s to travel along each side. What is its average speed for the complete journey?


A 2 m/s
B 3 m/s
C 4 m/s
D 5 m/s
Show Answer & Solution

✓ Correct Answer: C — 4 m/s

🧠 Concept

How to analyse the problem: The particle travels along all three sides of a triangle. Therefore, the total distance is the sum of the lengths of all three sides.

How to crack it: Add the distances travelled along the three sides to obtain the total distance. Then add the time taken for each side to obtain the total time. Finally, use total distance divided by total time.

Basic formula:

vavg = stotal ttotal

For motion along three sides:

stotal = s1 + s2 + s3

The total time is:

ttotal = t1 + t2 + t3

Conclusion: When a particle moves along the sides of a triangle, calculate the actual distance covered along each side and add all the distances before calculating average speed.

💡 Solution

Step 1: Find the total distance

The triangle is equilateral, so all three sides have the same length.

stotal = 20 + 20 + 20
stotal = 60 m

Step 2: Find the total time

The particle takes 5 s along each side.

ttotal = 5 + 5 + 5
ttotal = 15 s

Step 3: Find the average speed

vavg = 60 15
vavg = 4 m/s
Answer: (3) 4 m/s